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UBSE • Class X • Science • Ch 1
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Chemical Reactions and Equations

In Class 7 Mathematics, Chapter 15 "Finding the Unknown" culminates the algebraic journey with Linear Equations in One Variable. Rooted in the 2026–27 NCERT Ganita Prakash curriculum, this master material uses the Balance Scale Model to teach the fundamental laws of equality, systematic inverse operations, the transposition shortcut, removing brackets, and modeling real-world word problems.

⚖️ Have You Ever Wondered?

How does a pan balance solve algebraic mysteries?

Imagine a balanced grocer's scale: on the left pan sits an unmarked brown bag of sugar plus a $2\text{ kg}$ metal weight. On the right pan sits a $7\text{ kg}$ metal weight. The scale rests perfectly level.

How much sugar is in the mystery bag? Without ripping open the bag or guessing, you simply lift the $2\text{ kg}$ weight off the left pan. To keep the scale balanced, you take $2\text{ kg}$ off the right pan as well! Instantly, the mystery bag balances with $5\text{ kg}$.

This simple physical act is the heart of all algebra: $$x + 2 = 7 \implies x = 7 - 2 = \mathbf{5}$$ An equation is a balanced scale, and solving for the unknown is simply peeling away outer weights until the mystery variable stands alone.

Why This Chapter Matters

In Class 7 Mathematics, Chapter 15 "Finding the Unknown" culminates the algebraic journey with Linear Equations in One Variable. Rooted in the 2026–27 NCERT Ganita Prakash curriculum, this master material uses the Balance Scale Model to teach the fundamental laws of equality, systematic inverse operations, the transposition shortcut, removing brackets, and modeling real-world word problems.

Before You Begin (Prerequisites)

  • Algebraic expressions and terms from Chapter 4.
  • The Distributive Property: $a(b + c) = ab + ac$.
  • Integer arithmetic rules from Chapter 10.

What You Will Learn (Core Objectives)

  • Formulate linear equations from verbal descriptions and balance scale diagrams.
  • Explain why maintaining equality requires performing identical operations on both sides.
  • Solve linear equations systematically using inverse operations and transposition.
  • Solve equations containing brackets and variables on both sides ($ax + b = cx + d$).
  • Translate and solve real-world word problems (age problems, perimeter, and consecutive integers).

Chapter Roadmap & Progression

1 1. The Anatomy of an Equation & The...
2 2. The Transposition Method: Fast S...
3 3. Solving Word Problems by Setting...

Complete Concept Guide (100% Curriculum Coverage)

1. The Anatomy of an Equation & The Balance Scale Model

1. The Intuition

An algebraic expression like $3x + 5$ is a phrase (it has no equal sign). An equation is a complete mathematical sentence stating that two expressions have the exact same numerical value:

$$\mathbf{3x + 5 = 20}$$

The left-hand side ($\text{LHS}$) must balance the right-hand side ($\text{RHS}$). A solution (or root) is the specific number that makes the equation true when substituted for the variable.

2. The Four Balance Scale Axioms

An equation remains balanced if and only if you treat both sides equally:

  1. Add the same number to both sides: $x - 3 = 7 \implies x - 3 + 3 = 7 + 3 \implies x = 10$.
  2. Subtract the same number from both sides: $x + 4 = 9 \implies x + 4 - 4 = 9 - 4 \implies x = 5$.
  3. Multiply both sides by the same non-zero number: $\frac{x}{3} = 5 \implies \frac{x}{3} \times 3 = 5 \times 3 \implies x = 15$.
  4. Divide both sides by the same non-zero number: $4x = 24 \implies \frac{4x}{4} = \frac{24}{4} \implies x = 6$.
3. Concrete Worked Example

Example: Solve the equation showing each balancing step: $$2x + 7 = 19$$

Step 1 (Isolate term with variable): Subtract $7$ from both sides:

$$2x + 7 - 7 = 19 - 7 \implies 2x = 12$$

Step 2 (Isolate the variable): Divide both sides by $2$:

$$\frac{2x}{2} = \frac{12}{2} \implies \mathbf{x = 6}$$

Check: $\text{LHS} = 2(6) + 7 = 12 + 7 = 19 = \text{RHS}$. Verified!

4. Pitfall & Examiner Trap
⚠️ Trap: Operating on Only One Side
Subtracting $7$ from the left side while leaving the right side as $19$ tilts the balance immediately! Whatever operation you perform on one side, you MUST perform identically on the other side.
5. Why This Matters in Life

Chemical equations in science (like $2\text{H}_2 + \text{O}_2 = 2\text{H}_2\text{O}$) obey this exact balance law: the number of atoms on the left must match the right.

2. The Transposition Method: Fast Solving Shortcut

1. The Intuition

Writing $+3$ or $-3$ on both sides takes extra time. Notice what happens when you shift a term to the other side: adding $3$ to both sides of $x - 3 = 7$ makes the $-3$ disappear on the left and appear as $+3$ on the right ($x = 7 + 3$).

Shifting a term across the equality sign is called Transposition.

2. Transposition Sign Rules

Crossing the "$=$" sign inverts the operation:

  • $+$ becomes $-$ (e.g. $x + 5 = 12 \implies x = 12 - 5 = 7$)
  • $-$ becomes $+$ (e.g. $x - 8 = 10 \implies x = 10 + 8 = 18$)
  • $\times$ becomes $\div$ (e.g. $5x = 35 \implies x = \frac{35}{5} = 7$)
  • $\div$ becomes $\times$ (e.g. $\frac{x}{4} = 6 \implies x = 6 \times 4 = 24$)
3. Concrete Worked Example (Variables on Both Sides)

Example: Solve: $5x - 8 = 2x + 7$

Step 1 (Transpose variable terms to LHS): Shift $+2x$ to left as $-2x$:

$$5x - 2x - 8 = 7 \implies 3x - 8 = 7$$

Step 2 (Transpose constants to RHS): Shift $-8$ to right as $+8$:

$$3x = 7 + 8 \implies 3x = 15$$

Step 3 (Divide): $x = \frac{15}{3} \implies \mathbf{x = 5}$.

4. Pitfall & Examiner Trap
⚠️ Trap: Forgetting to Flip Signs During Transposition
In $x + 9 = 20$, writing $x = 20 + 9 = 29$ is a careless error. A positive term crossing the equal sign MUST become negative: $x = 20 - 9 = 11$.
5. Why This Matters in Life

Financial calculators find missing interest rates or loan repayment months by transposing standard compound interest formulas.

3. Solving Word Problems by Setting Up Equations

1. The 4-Step Word Problem Blueprint
  1. Identify the Unknown: Assign a letter (e.g. $x$) to the unknown quantity.
  2. Translate the Story into Math: Use words like "sum" ($+$), "difference" ($-$), "times" ($\times$), and "is/equals" ($=$).
  3. Solve the Equation: Use transposition to find $x$.
  4. Check in the Original Story: Ensure the answer makes real-world sense (ages and lengths cannot be negative!).
2. Concrete Worked Example (Age Puzzle)

Problem: Maya's father is $4$ years older than three times Maya's age. If her father is $40$ years old, find Maya's age.

Step 1: Let Maya's age be $m$ years.

Step 2: "Three times Maya's age" $= 3m$. "4 years older" $= 3m + 4$.

Step 3: Form equation: $3m + 4 = 40$

Step 4: Transpose $4$: $3m = 40 - 4 = 36$

Step 5: Divide by $3$: $m = \frac{36}{3} = \mathbf{12\text{ years old}}$. (Check: $3 \times 12 + 4 = 40$. Matches!).

3. Why This Matters in Life

Business entrepreneurs use linear break-even equations ($\text{Revenue} = \text{Costs}$) to determine exactly how many products they must sell before turning a profit.

Visual Learning & Conceptual Map

The Balance Scale Model of an Equation ($2x + 3 = 11$)

Removing 3 from both pans isolates $2x = 8$, yielding $x = 4$
LEFT PAN (LHS)
$2x + 3$
Mystery bags + 3 weights
=
RIGHT PAN (RHS)
$11$
11 total weights

Chapter Summary & 10 Key Takeaways

Takeaway 1
Equation: A statement of equality between two mathematical expressions containing at least one variable.
Takeaway 2
Solution: The numerical value of the variable that makes the equation true ($\text{LHS} = \text{RHS}$).
Takeaway 3
Balancing Principle: Adding, subtracting, multiplying, or dividing both sides by the same non-zero quantity preserves equality.
Takeaway 4
Transposition: Shifting terms across the equal sign reverses their operation ($+ \leftrightarrow -, \times \leftrightarrow \div$).
Takeaway 5
Solving Strategy: Collect variable terms on one side and constants on the other, then divide by the coefficient.

Check Your Understanding (Diagnostic Practice Questions)

Diagnostic questions testing core conceptual clarity. Answers are hidden initially — solve each problem first, then click to reveal the step-by-step verified solution.

1
Solve the equation: $3(x - 2) = 15$
Reveal Answer & Explanation
Answer: $x = 7$
Divide both sides by $3$: $x - 2 = 5$. Then transpose $-2$: $x = 5 + 2 = 7$.
2
Solve: $4x + 3 = 2x + 11$
Reveal Answer & Explanation
Answer: $x = 4$
Transpose $2x$: $4x - 2x + 3 = 11 \implies 2x + 3 = 11$. Transpose $3$: $2x = 8 \implies x = 4$.
3
The sum of three consecutive integers is $51$. Find the three integers.
Reveal Answer & Explanation
Answer: $16, 17, 18$
Let integers be $x, x+1, x+2$. $x + (x+1) + (x+2) = 51 \implies 3x + 3 = 51 \implies 3x = 48 \implies x = 16$.
4
The perimeter of a rectangle is $28\text{ cm}$. If its length is $8\text{ cm}$, find its breadth using an algebraic equation.
Reveal Answer & Explanation
Answer: $6\text{ cm}$
$2(l + b) = 28 \implies 2(8 + b) = 28 \implies 8 + b = 14 \implies b = 14 - 8 = 6\text{ cm}$.
5
Check whether $x = -3$ is a solution to $5x + 12 = -3$.
Reveal Answer & Explanation
Answer: Yes, $x = -3$ is the correct solution.
Substitute: $\text{LHS} = 5(-3) + 12 = -15 + 12 = -3 = \text{RHS}$.
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